160=5x^2+50x+24

Solution for 160=5x^2+50x+24 equation:

160=5x^2+50x+24

We move all terms to the left:

160-(5x^2+50x+24)=0

We get rid of parentheses

-5x^2-50x-24+160=0

We add all the numbers together, and all the variables

-5x^2-50x+136=0

a = -5; b = -50; c = +136;
Δ = b2-4ac
Δ = -502-4·(-5)·136
Δ = 5220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5220}=\sqrt{36*145}=\sqrt{36}*\sqrt{145}=6\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-6\sqrt{145}}{2*-5}=\frac{50-6\sqrt{145}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+6\sqrt{145}}{2*-5}=\frac{50+6\sqrt{145}}{-10}
$